22x^2-21xy+5y^2=

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Solution for 22x^2-21xy+5y^2= equation:


Simplifying
22x2 + -21xy + 5y2 = 0

Reorder the terms:
-21xy + 22x2 + 5y2 = 0

Solving
-21xy + 22x2 + 5y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(2x + -1y)(11x + -5y) = 0

Subproblem 1

Set the factor '(2x + -1y)' equal to zero and attempt to solve: Simplifying 2x + -1y = 0 Solving 2x + -1y = 0 Move all terms containing x to the left, all other terms to the right. Add 'y' to each side of the equation. 2x + -1y + y = 0 + y Combine like terms: -1y + y = 0 2x + 0 = 0 + y 2x = 0 + y Remove the zero: 2x = y Divide each side by '2'. x = 0.5y Simplifying x = 0.5y

Subproblem 2

Set the factor '(11x + -5y)' equal to zero and attempt to solve: Simplifying 11x + -5y = 0 Solving 11x + -5y = 0 Move all terms containing x to the left, all other terms to the right. Add '5y' to each side of the equation. 11x + -5y + 5y = 0 + 5y Combine like terms: -5y + 5y = 0 11x + 0 = 0 + 5y 11x = 0 + 5y Remove the zero: 11x = 5y Divide each side by '11'. x = 0.4545454545y Simplifying x = 0.4545454545y

Solution

x = {0.5y, 0.4545454545y}

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